x^2+300x=6504000

Solution for x^2+300x=6504000 equation:

x^2+300x=6504000

We move all terms to the left:

x^2+300x-(6504000)=0

a = 1; b = 300; c = -6504000;
Δ = b2-4ac
Δ = 3002-4·1·(-6504000)
Δ = 26106000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{26106000}=\sqrt{400*65265}=\sqrt{400}*\sqrt{65265}=20\sqrt{65265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-20\sqrt{65265}}{2*1}=\frac{-300-20\sqrt{65265}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+20\sqrt{65265}}{2*1}=\frac{-300+20\sqrt{65265}}{2}
$